模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图2 本模拟考试旨在尽可能逼真地模拟 IIS 考试帮助你创造一个实际考试环境题目涵盖第 1 章至第 7 章且为多项选择题

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图6 考试时时间限制是一个大问题因此我们建议在做这套题时身边放一闹钟以便在模拟考试过程中掌握时间设定好时间后即可开始

K r is t in is th e N T a d m in is tra to r fo r D . S .C o n s u
lting, a s m a ll c o m p a n y w ith on ly o n e s e rv er, A L IE N . S h e h a s b een to ld to im p lem e n t an I IS 4 in tran et a n d e n a b le a nony m ous a c c e s s . W h a t is th e na m e of th e W W W a nony m ous a c c oun t, as s u m in g th e d e fa u lts are u s ed ?

A. A d m in is tra to r B . A nony m ous

C . IU S R _ A L IEN

D. IU S R _ D

E . IU S R _D _S _C O N S U L T IN G

E v a n ha s be c o m e ve ry c onc e rne d a bout s e c u r ity a t
h is s ite be c a u s e s e ve ra l ne w s pa pe rs ha v e b e e n runn ing re ports a bout W W W bre a k - ins . H is b o s s is ev en m o re w o r r ie d a n d te lls h im to im p lem en t th e u s e o f certificates n o w , if not s oone r . W h ic h u tility in In te rn e t S e rv ic e M a n a ge r is us e d to is s u e

certificates ?

A . C e r tif ic a te M a na ge r B . S ite M a na ge r

C . K e y M a na ge r

D . C e rtific a te L o rd

T h e s c oundre ls in T e c h S upport ha ve be e n a c c e s s ing
m a c h in e s th e y s hou ld not a t o th e r s ite s w ith in S y ne rg y C o rpora tion a nd w re a k ing ha voc . I t is de c ide d th a t no one c o m ing f ro m th e T e c h S uppo r t s e rv e r s hou ld be a l lo w e d acce s s to th e W e b s e rv e r . H o w s hou ld acces s to th at s e rv er b e d e n ied , as s u m in g a s in g le d o m ain ? ( S e lect th e b e s t an s w er)

A . B y IP a ddre s s

B . B y dom a in na m e

C. By u s e r

D . B y certificate

T o a l le v ia te s e c u r ity c o nc e rns , y ou de c ide to us
e W indow s N T C h a lle nge / R e s p ons e a s y our m e th o d of a u th e n tic a t ion. W h ic h brow s e rs c a n n o w acces s y o u r s ite ?

A . In te rn e t E xp lore r 2 .0 B . N e ts c a pe 2 .0

C . In te rn e t E xp lore r 3 .0

D. N e ts c a p e 3 . 0

5 . W h ic h N T F S p e rm is s io n a s s ig n s o n ly th e c a p a b ilitie s to re a d a n d e x e c u te ?

A . F u ll C o n tro l

R e a d
Ch a n g e
No A c c e s s
S p e c ia l

6. S e c u re S o c k e ts L a y e r ( S S L ) c a n be us e d w ith w h ic h ty pe s of us e rs ?

A . S p ecific u s ers o n ly
B . A nony m ous us e rs on ly
C . S p e c if ic or a nony m o u s us e r	s
D . S S L is not us e d w ith u s e rs
7. O n a n N T s e rv e r , w h ic h f i le	c a n be us e d on	a	s m a ll	ne tw ork	fo r	th e	s ta t ic
re s o lu t ion of hos t na m e s to IP	a ddre s s e s ?
A. HOS T S
B . LM H O S TS
C . DNS
D. W INS
8 . O n an N T s e rv er, w h ic h f ile	can b e u s ed o n	a	s m all	n e tw o rk	fo r	th e	s tatic
re s o lu t ion of N e t B IO S na m e s	to IP a ddre s s e s ?
A. HOS T S
B . LM H O S TS
C . DNS
D. W INS

O n a n N T s e rv e r , w h ic h s e rv ic e c a n be us e d on a

la rg e ne tw ork fo r th e dy na m ic re s o lu t ion of hos t na m e s to IP a ddre s s e s ?
1. HOS T S

B . LM H O S TS C . DNS

D. W INS

O n a n N T s e rv e r , w h ic h s e rv ic e c a n b e us e d on a

la rg e ne tw ork fo r th e dy na m ic re s o lu t ion of N e t B IO S na m e s to IP a ddre s s e s ?
1. HOS T S

B . LM H O S TS C . DNS

D. W INS

L e opo ld is a tte m p ting to e v a lua te h is c u r re nt e qu

ipm e n t fo r s u ita b ility fo r hos ting a W e b s ite . W h a t is th e m in im u m m on ito r re qu ire m e nt of I IS 4 ?
1. C G A B . VGA

C . S VGA

D. XGA

I f th e W W W hom e d ire c tory is a re d ire c tion to a s h a re
on a no the r c o m pu te r , y ou m u s t g ive th e U N C to th a t s h a re . U N C is a n a c rony m fo r w h ic h of th e fo llo w in g ?

A . U n iv e rs a l N a m ing C onve n tio n

B . U n iv e rs a lly N a m e d C o m p u te r C . U n ila te ra l N a m in g C o n v e n tio n D . U n ila te ra lly N a m e d C o m p u te r

W h ic h of th e fo llo w ing is a n e x a m p le of a U N C ? A .
\\ s erv e r \ s h are

B . //s e rv e r / s h a re C . \\s h a re \s e rv e r D . //s h a re /s e rv e r

T ony is s e tting u p a n I IS s e rv e r ( a nd N T ) c o m p le

te ly f rom s c ra tc h a nd h a s no e xpe r ie n c e w ith do ing s o . H e ha s run a c ros s s e ve ra l d if fe re nt w a y s of re fe re nc ing h is c o m pu te r . O n e of th e s e is a s 192 .2 .2 .5. T h is is a n e x a m p le of w h ic h o f th e fo llo w in g ?
1. F QDN
2. M A C a d d re s s C . IP a ddre s s

D. N e t B IO S n a me

A no th e r w a y T ony ha s found to re fe re nc e h is c o m pu te

r is 44- 45- 53- 54- 00- 00. T h is is a n e x a m p le of w h ic h of th e fo l low ing?
1. F QDN

B . M A C a ddre s s C . IP a ddre s s

D. N e t B IO S n a me

1 6 . In a m u ch s im p le r fa s h io n , T o n y can re fe re n ce h is co m p u ter as D _ S _ S e rv er.

T h is is be s t a n e x a m p le of w h ic h of th e fo llow ing?

F QDN
M A C a d d re s s C . IP a ddre s s

D. N e t B IO S n a me

1 7 . F in a l ly , T o n y c a n a ls o re fe re n c e h is c o m p u te r a s www. ro g u e m d c . c o m . T h is is a n e x a m p le of w h ic h of th e fo llo w ing?

F QDN
M A C a d d re s s C . IP a ddre s s

D. N e t B IO S n a me

18. L a ndon J a m e s ha s ju s t f in is h e d a dd ing th e F T P s e rv ic e to h is I IS 4 .0 s e rv e r . W h a t d ire c to ry w a s c re a te d d u rin g th e in s ta lla tio n o f th is s e rv ic e ?

A . c :\ ine tpub \f tp

B . c :\ ine tpub \ f tproot C . c :\in e tpub \roo tf tp

D . N o a dd itiona l d ire c tory w a s c re a te d

9 . W h at d irecto ry acces s co n tro l m u s t L a ndon J a m e s

a dd to a d ire c tory in orde r fo r a n F T P us e r to be a b le to dow n loa d f ile s f ro m th a t d ire c tory ?
1. E x e c u te
2. R e a d
3. C re a te D . M od ify E . C h a nge
0 . B a n d w id th is a m a jo r is s u e fo r M c k e n z ie . H e

r L A N u s e rs a re c o m p la in in g th at th ey a re b e in g d e n ied ac ces s to s e rv er f ile s s in ce th e s e rv er b e c a m e th e W W W hos t. T o be tte r s e rv e he r L A N us e rs , M c ke nz ie s hou ld im p le m e n t w h ic h o f th e fo llo w in g ?

A . H T T P k eep - a liv es B . B a ndw id th c h ok ing

C . L im ite d c onn e c tions D . B a n d w id th th ro ttlin g

E . U s e r logon re qu ire m e n ts

I IS 4 .0 c onfigura tion va lu e s , fo r th e m o s t p a r t, a
re s to re d w h e re in m e m o ry ? A . T e x t file s

B . A c c e s s da ta ba s e s

T h e R e g is try D . IIS m e ta b a s e

E . In fo rm a t io n s to re

T h e tool us e d to re m o te ly m a na ge y our W e b s ite us ing
a s ta nda rd In te rn e t brow s e r is w h ic h of th e fo llo w ing?

A . In te rn e t S e rv ic e M a n a g e r (H T M L ) B . M M C

C . C o n ten t A n a ly z er D . S e rv e r M a na ge r

R o b fe a rs th a t th e N T s e rv e r th a t is hos ting h is I
IS s ite is a c ting up. H e ne e d s to c h e c k th e s y s te m log to ve r ify h is hunc he s . W h a t tool c a n he us e to c h e c k th e syste m lo g ?

A . A n y te x t e d ito r

B . In te rn e t S e rv ic e M a n a g e r C . M M C

D . E v en t V iew er

T h e de fa u lt s ubne t m a s k a s s igne d to a n IP a ddre s s
of 100 .100 .100 .200 is w h ic h o f th e fo llo w in g ?

A . 0 .0 .0 .0

B . 255 .0 .0 .0

C . 255 .255 .0 .0

D . 255 .255 .255 .0

2 5 . H o w can y o u te s t th e in s talla tio n o f an F T P s e rv er?

A . P ing th e F T P loopba c k a ddre s s B . P ing a no the r F T P s e rv e r

C . F T P a no the r s e rv e r

D . F T P th e loopba c k a ddre s s

In th e D N S na m e w w w . a m a z on .c o m , w h a t doe s *am
azon* re p res en t? A . T h e la s t na m e of th e hos t

B . T h e d o m a in in w h ic h th e h o s t is lo c a te d

C . T h e IP a d d re s s o f th e b u ild in g in w h ic h th e h o s t is lo c a te d D . T h e d ire c to ry in w h ic h th e h o s t n a m e file is lo c a te d

J a c k is a c ons u lta nt c a lle d in to a d v is e M c B r id e

, In c . on how to s e t up its W e b s ite . M c B r id e w a n ts to us e I IS in a w a y th a t us e rs m u s t g ive a va l id us e rna m e an d p a s s w o rd to g a in acces s . A ll th e u s ers are u s in g th e la te s t v e rs io n o f E xp lo re r a s th e ir brow s e rs . W h ic h a u th e n tic a t ion m e thod s hou ld J a c k reco m m e n d ?
1. B a s ic T e x t

B . A n y a u th e n tic a t ion m e thod C . N T C h a lle nge / R e s pons e

D . SSL

W h a t F T P pe rm is s ion is ne e d e d fo r us e rs to be a b le

to up loa d f ile s to a d ire c tory ?
1. W r ite
2. E x e c u te
3. R e a d

D . C h a nge E . M od ify

J a ne is a tte m p ting to a lte r th e T C P port a s s ignm e n

ts on he r s e rv e r to h ide s e ve ra l s e rv ic e s . T h e de fa u lt port fo r W W W S S L is w h ic h of th e fo llo w ing?
1. 2 1
2. 2 5
3. 8 0 D . 110 E . 443
J a ne know s th a t s h e de f in ite ly w a n ts to h ide th e W W

W s e rv ic e . T h e de fa u lt port fo r i t is w h ic h of th e fo llo w ing?
1. 2 1
2. 2 5
3. 8 0 D . 110 E . 443
W h a t is th e m a x im u m num be r o f S M T P s im u l ta n e

ous c o n n e c tions a llo w e d by d e fa u lt?
1. 1 0 B . 500

C . 1000

D . 5000

J e nna ne e d s to ge t to th e S M T P prope r ty s h e e ts to m
a ke m od if ic a tions . T h e s e are acc es s e d v ia w h ic h o f th e fo llo w in g ?

A . S M T P M a na ge r

B . In te rn e t S e rv ic e M a n a g e r

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图11 C . T h e C on tro l P a ne CM T P ic o n

D . T h e S e tu p u tility fo r I IS

T h e de fa u lt n u m b e r of in a c tiv e s e c onds be fo re a n

S M T P d is c onne c t is w h ic h o f th e fo llo w in g ?
1. 3 0
2. 6 0 C . 600 D . 900 E . 999
M a ry K a y is us ing S S L a nd N N T P . A s s u m ing no c h a n

g e s ha ve be e n m a de m a nua lly , w h a t is th e de fa u lt T C P p o r t th a t N N T P is us ing?
1. 2 5
2. 8 0 C . 119 D . 563
M a ry K a y ha s s toppe d us ing S S L b ecau s e th ere is n o t

a n eed at h e r s m all s i te ( w h ic h doe s not offe r ou ts ide a c c e s s ) . A s s u m ing no c h a nge s ha ve be e n m a de m a nua lly , w h a t is th e T C P port a s s ignm e n t th a t N N T P is us ing?
1. 2 5
2. 8 0 C . 119 D . 563
W h e n D a is ha c re a te s a ne w ne w s group by th e na m e F r

id a y , N N T P w i ll

au to m a t ically crea te a n e w d ire cto ry to h o ld th e articles . T h e n a m e o f th e d ire c to ry w ill b e w h ic h o f th e fo llo w in g ?

A . F r id a y .nn tp B . F r id a y .x ix C . F r id a y .n w s

F r id a y
D a is h a

H o w m a ny a r tic le s c a n a s ing le N N T P inde x ho ld? A .
U n lim ite d a r t ic le s

B . 256

C . 128

D . N N T P articles are n o t in d e x e d

A la n a ha s ju s t in s ta l le d th e N N T P s e rv ic e on he r
s e rv e r a nd us e d th e de fa u lt s e ttings to do s o . W h a t d ire c tory w a s c re a te d during th e in s ta lla t ion?

A . % S y s te m R oo t% \ S y s te m 32 \ N N T P B . % S y s te m R oo t% \ Inne tpub \N N T P

C . % S y s te m R oo t% \ Inne tpub \N N T P R O O T

D. % S y s te m R o o t% \ S y s te m 3 2 \ NNT P R OOT E . N o ad d itio n a l d irecto r ie s are cre a te d

M ic h a e l is try ing to f ind th e M IM E m a pp ings fo r h is s
ite . W h e re a re th e y sto re d ?

A . In te x t file s

B . In . X IX file s

C. In th e R e g is try D . In th e m e ta b a s e

E . In th e M IM E M a n a g e r

4 0 . H a n n a h h a s e lected to create F T P lo g f ile s to k eep trac k o f th e traffic s h e is g e ttin g . W h ere ca n s h e f in d th es e f ile s as th ey are create d ?

A . % S y s te m R oo t% \ Inne tp u b \ logfile s B . \L o g file s

C . % S y s te m R oo t% \ S y s re m 32 \ logfile s

D. \ e tc

W h ic h of th e fo llo w ing ope ra to rs c a n be u s e d in . H T

X f ile s ?
1. C ONT A INS
2. IN CL U D E S
3. E Q
4. M T
W h ic h of th e fo llo w in g f ile s is re s pons ib le fo r pro v

id ing O D B C func tiona lity in IIS ?
1. HT T P .A P I B . H TTP . D LL

C. H T T P O D BC .A P I

D. HT T P ODB C . DL L

W h ic h pa ra m e te r s hou ld E v a n us e in h is .ID C f ile to
trunc a te e n tr ie s th a t

ex ce ed a ce r tain s ize? A . M a x R eco rd s

B . M a x F ie ld S iz e C . T ru n c ateS iz e

D . M a x T ru n cateS iz e E . M a x R eco rd S ize

A f te r a que ry ha s be e n proc e s s e d by Inde x S e rv e r ,

th e re s u l ts a re s e nt to w h a t ty p e o f file to u s e a s a te m p la te fo r fo rm a ttin g th e re s u lt?
1. T M X
2. ID Q
3. T E M
4. HT M
5. H T X
A s inpu t, Inde x S e rv e r us e s f i le s w i th w h a t e x te

ns ion?
1. .T M X
2. . ID Q C . . TEM

D. .H T M

E. . H TX

A r th u r is try ing to de te rm in e w h a t pe rm is s ions a re

ne e d e d on ID Q f ile s fo r th e m to func t ion prope r ly . W h ic h tw o of th e fo llow ing a re c o r re c t?
1. S c r ip t
2. E x e c u te
3. R e a d
4. W r ite

E . C h a nge

W h ic h of th e fo llo w ing ta gs a re op tio n a l in a n ID Q f
ile ? A . [Q u e ry ]

B . [ Q u e ry D e ta il] C . [ B e g in D e ta il] D . [ N am es ]

4 8 . H o w m a n y c h aracte rs can b e u s ed in th e p a th s p ecificatio n fo r a te m p la te ?

A . U n lim ite d ch a racters B . 260

C . 256

D . 255

E. 8

W h ic h of th e fo llo w ing f ile s c a n c on ta in que r ie s ?
1. HT X
2. H T M
3. ID C
4. ID Q
W h ic h c h a ra c te r is us e d in a s c r ipt f ile to pre v e n

t a lin e f rom be ing proc e s s e d?

A. +

T ra c y is try ing to f ind th e C s c r ip t pa ra m e te r us e d
to s a ve th e c u r re n t c o m m a nd l ine fo r th e us e r . I t is w h ic h of th e fo llow ing?

A . //C

B . //I

C . //B

D . //S

E . //R

T ra c y is now try ing to f ind th e C s c r ip t pa ra m e te r us

e d to re g is te r s c r ipt e x te n s io n s . I t is w h ic h o f th e fo llo w in g ?
1. // C B . //I C . //B D . //S

E. // R

J e f f is de ba ting w h e the r to us e C G I or IS A P I to w r
ite th e progra m he ne e d s . W h a t a re th e a dva n ta g e s of IS A P I ove r C G I?

A . I t is lo a d e d in to m e m o ry o n f irs t c a ll B . It ru n s a s a T S R

C . It is re u s a b le

D . I t ru n s as a D L L

W h ic h of th e fo llo w ing is true of A c t ive S e rv e r P a ge
s ? A . T h e y m u s t ha ve . A S P e x te ns ions

B . T h e y can h a v e an y ex te n s io n

C . T h e y c a n c on ta in s ta nda rd H T M L ta gs

D . T h e y c a nno t c on ta in s ta nda rd H T M L ta gs

A rd ith is s e le c t ing W W W log f i le s to be c re a te d b a

s e d on s iz e ra th e r th a n da te , m on th, a nd s o on. W h a t de fa u lt f ile s iz e is us e d ?
1. 1 M B
2. 9 M B C . 19M B D . 91M B

答案与题解

C

在 AL IE N 服务器上缺省的匿名帐号用户名为 IU S R _ A L IEN ( 第 1 章 )
C

K e y M a n a g e r用以处理证书事务 ( 第 2 章 )
A

最好的解决办法是不允许使用 IP 地址访问该服务器 ( 第 3 章 )
A

, C W ind ow s N T C h a lle ng e / R e s pons e 认证需要有 In te rn e t E xp lore r 2 .0 或更高版本 ( 第 7 章 )
B

R ead 权限允许读和执行操作 ( 第 3 章 )
C

特殊或匿名用户使用 SSL ( 第 1 章 )
A

HOS T S 文件用以将静态主机名解析为 IP 地址 ( 第 7 章 )
B

LM H O S TS 文件用以将动态主机名解析为 IP 地址 ( 第 7 章 )
C

DNS 用以将动态主机名解析为 IP 地址 ( 第 7 章 )
D

W IN S 用以将动态 N e t B IO S 名解析为 IP 地址 ( 第 7 章 )
C

IIS 4 要求用 S VGA 监视器 ( 第 1 章 )
A

UNC 是 U n iv e rs a l N a m ing C onve n tio n 的缩写 ( 第 2 章 )
A

\\s e rv e r\\s h a re 是一个 UNC 示例 ( 第 2 章 ) 14. C 192 .2 .2 .5 是一个 IP 地址 ( 第 7 章 )

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图42 15. B 44- 45- 53- 54 - 00- 00 是一个 M A C 地址 ( 第 1 章 )

D

D _ S_ Se rv e r是一个 N e t B IO S 名称 ( 第 1 章 )
A

www. rogue m d c . c o m 是一个 F u lly Q u a lif ie d D o m a in N a me ( F QDN )( 第 7

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图47 章 )

B

在安装 FT P 服务时要创建 c :\in e tpub \f tproo t目录 ( 第 2 章 )
B

要用 FT P 下载文件必须有 R ead 权限 ( 第 7 章 )
D

带宽节流将减少 W W W 服务使用的带宽量 ( 第 6 章 )
D

m e ta b a s e 存放着 IIS 的驻留内存值 ( 第 2 章 )
A In

te rn e t S e rv ic e M a n a g e r (H T M L ) 是远程管理使用标准 In te rn e t浏览器的

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图57 W e b 站点的工具 ( 第 2 章 )

D
E v e n t V iew er用以检查系统记录 ( 第 6 章 )

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图60 24. B 赋给 IP 地址 100 .100 .100 .200 的缺省子网掩码是 255 .0 .0 .0 因为其为一 A

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图62 类地址 ( 第 7 章 )

D

通过 FT P 回馈地址可测试 FT P 的安装 ( 第 7 章 )
B

该路径设定主机名 www 在域 am azo n 上而域 am azo n 又在顶级域 .c o m

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图67 上 ( 第 7 章 )

C

在本例中 J ack 应推荐 N T C h a lle nge / R e s pons e 来增加安全性 ( 第 3 章 )
A

用户若要向一个目录上载文件应拥有 FT P W r ite 权限 ( 第 7 章 )
E

SSL 的缺省端口值为 443( 第 1 章 )
C

W W W 的缺省端口值为 80( 第 7 章 )
C

缺省情况下 SM T P 同时连接的最大数目为 1000( 第 3 章 )
B

SM T P 特性表单可通过 In te rn e t S e rv ic e M a n a g e r访问 ( 第 3 章 )
B

SM T P 断开连接的缺省非活动秒数为 60( 第 3 章 )
D

使用 SSL 的 NNT P T C P 端口值为 563( 第 3 章 )
C

未使用 SSL 的 NNT P T C P 端口值为 119( 第 3 章 )
D

名为 F rid a y 的新新闻组将自动创建一个名为 F rid a y 的目录 ( 第 3 章 )
C

一个单独的 NNT P 索引可容纳 128 个文稿词条 ( 第 3 章 )
C 安

装 NNT P 时会创建 % S y s te m R oo t% \ Inne tp u b \ N N T P R O O T 目录 ( 第 3

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图94 章 )

C

M IM E 映射保存在 R e g is try 中 ( 第 3 章 )
C

FT P 记录文件在 % S y s te m R oo t% \ S y s te m 32 \L ogfile s 中 ( 第 3 章 )
B

, C .H T X 文件运算符包括 EQ 和 C ONT A INS ( 第 4 章 )
D

IIS 中的 ODB C 功能由 HT T P ODB C . DL L 提供 ( 第 4 章 )
B

M a x F ie ld S iz e 参数决定何时截断超过某一大小的入口 ( 第 4 章 )
E

在 Inde x S e rv e r处理完一个查询后 ,结果传送到一个 .H T X 文件中以此作模板对该结果进行格式化 ( 第 4 章 )
B

Inde x S e rv e r使用带 .ID Q 扩展名文件作为输入 ( 第 4 章 )
A

B 若要正常使用 ID Q 文件需要拥有 Ex e c u te 和 Sc r ip t权限 ( 第 4 章 )
D

在 ID Q 文件中 [ N am es ] 段属任选项 ( 第 4 章 )
B

一个模板的路径可使用 260 个字符 ( 第 4 章 )
C

, D ID C 和 ID Q 文件中可包含查询 ( 第 4 章 )
D

# 号用在脚本文件中表示该字符后的一行内容不要处理 ( 第 4 章 )
D

/S S 是 C s c r ip t参数用以为用户保存当前命令行 ( 第 4 章 )
E

//R 是一个 C s c r ip t参数用以登记脚本扩展名 ( 第 4 章 )
A

, C , D IS A P I可在启动时装入内存可重新使用并可以 DL L 运行 ( 第 5

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图132 章 )

A , C
A c tiv e S e rv e r P a g e s 具有 .A S P 扩展名并可包含标准 HT M L 标志 ( 第 5

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4 - 图134 章 )

C
记录文件的缺省文件大小为 19M B ( 第 3 章 )

模 拟 考 试 1 In te rn e t In fo rm a tio n S e rv e r 4

模 拟 考 试 1 In te rn e t In fo rm a tio n S e rv e r 4

答 案 与 题 解

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4

模拟考试 1 In te rn e t In fo rm a tio n S e rv e r 4

答案与题解