模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4 - 图2 本模拟考试旨在尽可能逼真地模拟 IIS 考试帮助你创造一个实际考试环境题目涵盖第 1 章至第 7 章且为多项选择题

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4 - 图6 考试时时间限制是一个大问题因此我们建议在做这套题时身边放一闹钟以便在模拟考试过程中掌握时间设定好时间后即可开始

S p e n c e r ha s inhe r i te d th e s y s te m a d m in is tra to r re s pons ib ilitie s a fte r a n unfortuna te a c c ide nt invo lv ing th e pre v ious a d m in is tra to r . H e know s th a t s ta tic file s a re u s e d fo r IP a d d re s s re s o lu tio n n a m e ly HO S T S a n d L M HOS T S

a nd w a n ts to a dd c o m m e n ts to th e f ile s to unde rs ta nd th e m be t te r . W h a t ch ara c te r s ig n if ie s a co m m en t in th es e f ile s ?

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4 - 图13 2 . T h e W e b a d d re s s www .a m a z o n .c o m is know n a s w h ic h of th e fo llo w in g

A lia s
H o s t n a m e C . F QDN

D. DNS

K a re n ne e d s to ve r ify th a t hos ts on th e ne tw ork c a n
re a c h he r in tra n e t s e rv e r . T h e u tility us e d fo r c h e c k ing c onne c t ions is w h ic h of th e fo l low ing?

A . ch ec k

B. te s t

C. tra c e D . trac ert

E. p in g

W h ic h s e rv ic e , in c lude d w ith I IS , is us e d to up loa

d a nd d o w n lo a d f ile s ?
1. S M T P B . NNT P

C. F T P

D . W W W

W h ic h s e rv ic e , in c lude d w ith I IS , is us e d to hos t

ne w s group s ?
1. S M T P B . NNT P

C. F T P

D . W W W

6 . W h ic h s e rv ic e , in c lu d e d w ith I IS , is u s e d to e x c h a n g e m a il w ith th e In te rn e t?

A. S M T P B . NNT P

C. F T P

D . W W W

W h a t is th e s y n ta x us e d , by de fa u lt, fo r th e a nony
m ous F T P us e r a c c oun t? A . A nony m ous

B . A nony m ous _ co m pu te rnam e

C o m pu te rna m e _ anonym ous
IU S R _ co m pu te rnam e
co m pu te rnam e _IU S R

W h a t is th e s y n ta x us e d , by de fa u lt, fo r th e a nony
m ous W W W us e r a c c oun t? A . A nony m ous

B . A nony m ous _c om pu tsm am e

C o m pu te rne m e _a nony m o us
IU S R _ co m pu te rnam e
co m pu te rnam e _IU S R

M a donna is try ing to c onfigure D N S prope r ly a nd e xp la in
to he r s ta f f h o w to re fe re n c e s ite s b y F u lly Q u a lifie d D o m a in N a m e s . W h ic h o f th e fo llo w in g ite m s a re in a n F QDN?

A. H o s t n a me B . IP a ddre s s

Co m p a n y n a m e
N e t B IO S n a me

A l la n is us ing L M H O S T S to s ta tic a lly m a p N e t B IO
S na m e s to IP a ddre s s e s . H is bos s a s ks h im to e xp la in w h y he is do ing th is , a n d ju s t w h a t a N e t B IO S

n a m e is . W h ic h o f th e fo llo w in g is a n e x a m p le o f a N e tB IO S n a m e ? A . 192 .2 .2 .5

B . www .s y n e rg y . c o m C . D _ S_ Se rv e r

D . FF - FF - FF - F F

S v e n ha s be e n to ld by H a ns th a t he ha s four da y s to
put toge th e r a bud ge t of w h a t is ne e d e d fo r H A N S , In c . to ge t I IS 4 up a n d runn ing a s a W e b s ite . G ive n th a t, w h a t is th e ve ry m in im u m R A M re qu ire m e nt I IS 4 ne e d s on a n In te l- ba s e d m a c h in e ?

A . 96M B B . 48M B C . 32M B D . 16M B

8 M B

S v e n ne e d s to de te rm in e w h e the r ne w m a c h in e s a
re re qu ire d to upda te th e N T s e rv e r on w h ic h I IS w ill be in s ta lle d. W h a t m in im u m In te l p roc e s s o r s p e e d is n eed e d ?

A . 200M H z B . 190M H z C . 100M H z

D. 9 0 M Hz E . 75M H z

P oor S v e n m u s t a ls o c ons id e r purc h a s ing a n A lpha
m a c h in e to us e fo r hos tin g th e I IS s e rv er. W h at is th e m in im u m R A M re q u ire m e n t in th is cas e ?

A . 96M B B . 48M B C . 32M B D . 16M B

E. 8 M B

T h e IU S R _ co m pu te rnam e a c c ount c a n be a s s igne d
re gu la r N T F S pe rm is s ions th rough w h ic h u tility ?

A . In te rn e t S e rv ic e M a n a g e r B . S e rv e r M a na ge r

C . U s e r M a n a g e r fo r D o m a in s D . P e rfo rm a n c e M o n ito r

E. Ta s k M a n a g e r

T ra c k in g o f I IS s e rv ic e s a nd re s o u rc e us a g e c a
n be done th rough w h ic h u tility ?

A . In te rn e t S e rv ic e M a n a g e r B . S e rv e r M a na ge r

C . U s e r M a n a g e r fo r D o m a in s D . P e rfo rm a n c e M o n ito r

E. Ta s k M a n a g e r

1 6 . W h ic h u tility is a v a ila b le o n ly f ro m p re s s in g C tr l+ A lt+ D e l o r b y r ig h t-

c lic k ing in th e ta s kba r?

A . In te rn e t S e rv ic e M a n a g e r B . S e rv e r M a na ge r

C . U s e r M a n a g e r fo r D o m a in s D . P e rfo rm a n c e M o n ito r

E. Ta s k M a n a g e r

7 . J e r ry h a s b e e n to ld th a t th e F T P s e rv ic e is to

b e u s e d o n ly in te rn a lly - - th e re is to b e n o o u ts id e acce s s . A t th e s a m e tim e , a nony m o u s logon s hou ld be a llo w e d. J e r ry de te rm in e s th a t th e be s t s o lu tion is to c h a n g e th e de fa u lt port o f th e F T P s e rv ic e to " h id e " it f ro m th e o u ts id e w o r ld . W h a t is th e d e fa u lt port of F T P ?
1. 2 1
2. 2 5
3. 8 0 D . 125

J e r ry a ls o w a n ts to " h id e " th e W W W s e rv ic e f rom

th e ou ts ide w o r ld. W h a t is th e de fa u lt port fo r W W W ?
1. 2 1
2. 2 5
3. 8 0 D . 125
J e nn ife r ha s be e n in s tru c te d by J e r ry to m a ke th e

F T P port c h a nge s . In s o

do ing, s h e c o m e s a c ros s a prope r ty ta b a s k ing th a t s h e s p e c ify w h a t ty pe of lis tin g th e F T P lis tin g s a re g iv e n in . W h a t a re th e c h o ic e s s h e c a n s e le c t?

B . UNDC

C . M S - DOS

D. UNC

T h e F T P hom e d ire c tory c a n be w h ic h of th e fo llo w
ing? A . A d ire c tory lo c a te d on th is c o m pu te r

B . A d ire c tory s h a re d on a re m o te c o m pu te r C . A U R L to a n o th e r lo c a tio n

D . A te x t file

T h e W W W hom e d ire c tory c a n be w h ic h of th e fo llo w
ing? A . A d ire c tory lo c a te d on th is c o m pu te r

B . A d ire c tory s h a re d on a re m o te c o m pu te r C . A U R L to a n o th e r lo c a tio n

D . A te x t file

E dna ha s be e n to ld th a t s h e m u s t c h a nge s o m e of th
e I IS 4 R e g is try va lu e s . T o do s o , w h a t tool s hou ld s h e us e ?

A . S y s te m P o lic y E d ito r B . R e ge d t32

C . R e gc ha nge r

D . R e g is try M o d if ic a tion T ool

E . H iv e K in g

Y our ne tw ork prov ide s a W e b s e rv e r to th e In te rn e t

th rough a f ire w a ll. W h ic h of th e fo llo w ing pro toc o ls w ou ld us ua lly not b e a v a ila b le to a c lie n t o n th e o the r s ide of y our f ire w a ll?
1. HT T P
2. F T P

C . TF TP

D. T e ln e t

H T M L doc um e n ts a re tra n s fe r re d us ing th e H T T P pro
toc o l. O f th e fo l low in g s tate m e n ts , w h ic h accu ra te ly d e s c r ib e s th e H T T P p ro to c o l?

A . H T T P us e s th e nonc onne c tion- orie n te d c o m m un ic a tion fe a ture s of T C P / IP fo r d a ta tra n s fe r .

B . H T T P re qu ire s a us e rna m e a nd pa s s w o rd fo r a ll H T M L doc um e n ts .

C . T h e H T T P pro toc ol us e s th e c onne c tion- orie n te d c o m m un ic a tion fe a ture s o f T C P / IP fo r d a ta tra n s fe r .

D . H T T P c a n be u s e d on ly fo r te xt f ile s .

A n orga n iz a tion is a s s igne d th e ne tw ork ID 114 .0 .0 .0
by In te r N IC . T h e orga n iz a tion c u r re n tly ha s f ive s ubne ts w ith a bout 100 ,000 hos ts pe r s ubne t. T h e m a na ge m e nt w a n ts to d iv ide th e s ubne ts in to 25 ne w s ubne ts to m a ke e a c h s ubne t m o re m a na ge a b le . H o w m a ny b its a re us e d fo r th e c u s tom s ubn e t m a s k ?

A . 4 b its

B . 5 b its C . 6 b its D . 7 b its

6 . W h ic h o f th e fo l lo w in g a llo w s fo r m u ltip le f
ile s to a p p e a r a s if th e y a re in o n e lo c a tio n ?

A . V ir tu a l file

B . V ir tua l d ire c tory C . V irtu a l s e rv e r

D . V irtu a l IIS

N a nc y is p la n n ing he r I IS s ite . T h e f ile lo c a tion
lim ita tion fa c ing he r on v ir tua l d ire c rorie s is w h ic h of th e fo llow ing?

A . T h e y m u st re sid e o n th e sa m e W A N B . T h e y m u s t re s ide on th e s a m e dom a in C . T h e y m u st re sid e o n th e sa m e se rv e r D . T h ere are n o s u ch l im i ta tio n s

N a nc y c a n c re a te th e v ir tu a l d ire c torie s s h e ne e

d s th rough w h ic h of th e fo llo w ing too ls ?
1. D is k A d m in is tra to r

B . V ir tu a l A d m in is tra to r

C . U s e r M a n a g e r fo r D o m a in s D . In te rn e t S e rv ic e M a n a g e r

E . V ir tua l M a na ge r

H o s ting m o re th a n one s ite th rough a s ing le s e rv e r is
k now n a s w h ic h of th e fo llo w in g ?

A . V ir tu a l file

B . V ir tua l d ire c tory C . V irtu a l s e rv e r

D . V irtu a l IIS

V ir tu a l s e rv e rs a re a ls o know n a s w h ic h of th e fo
llo w ing? A . R ou te rs

B . B r idge s

C . G a te w a y s

D . M u ltih o m e d h o s ts

J a ne is a tte m p ting to a lte r th e T C P port a s s ignm e n

ts on he r s e rv e r to h ide s e ve ra l s e rv ic e s . T h e de fa u lt port fo r S M T P is w h ic h of th e fo llo w ing?
1. 2 1
2. 2 5
3. 8 0 D . 110 E . 443
J o s e ph is ha v ing d if f ic u l ty w ith us e rs ha v in g a

ppropria te pe rm is s ions to pos t to N N T P ne w s groups . A u th e n tic a tion fo r N N T P pos ting is pe r fo rm e d by w h ic h o f th e fo llo w in g ?
1. NT

B . IIS

C . NNT P

D. S M T P

A u s tin is try ing to f ind out w h a t a l l th e d ire c torie s

a re on th e s e rv e r th a t he ha s inhe r ite d. O n e d ire c tory ha s s e ve ra l f i le s w ith .N W S e x te ns ions . T h e d ire c tory he ha s found is m o s t lik e ly w h ic h of th e fo llow ing?
1. An S M T P p o s t o f f ic e B . A n N N T P ne w s group

C. A C e r tif ic a te S e rv e r k e y D . T h e recy cle b in

E . In te rn e t S e rv ic e M a na ge r p lug- in s

T h e . X IX e x te ns ion on f ile s ind ic a te s th a t th e y a
re w h ic h of th e fo llo w ing? A . N e w s groups

B . Inde xe s C . A rtic le s

D. H e a d e r f ile s

A im e e is try ing to f ind th e M IM E m a pp ings to s e e w h e
the r s h e ha s th e .J P G f ile s prope r ly c onfigure d . W h e re a re th e M IM E m a p p ings fo r . J P G f ile s sto re d ?

A . In te rn e t S e rv ic e M a n a g e r

B. R e g is try

C . W W W p ro p e r tie s

D . S M T P p rope r tie s

6 . J o y c e h a s h e r W W W s ite c re a tin g d a ily lo g f
ile s . W h a t s y n ta x is u s e d to crea te th e f i le s ?

A . y y m m dd .lo g B . d d m m yy.lo g C . in e ts v # .lo g

D . in y y m m d d . lo g E . in d d m m y y .lo g

37. H o w m a ny F T P s im u l ta n e ous c onne c t ions a re a llo w e d on a s e rv e r by d e fa u lt? A . U n lim ite d

B . 1000

C . 500

D. 5 0

8 . S c o tt h a s e le c te d to c re a te W W W lo g f ile s to k
e e p tra c k o f th e tra f f ic h e is g e ttin g . W h ere c a n h e f in d th es e f i le s a s th ey a re c reated ?

A . % S y s te m R oo t% \ Inne tp u b \ logfile s B . \L o g file s

C . % S y s te m R oo t% \ S y s te m 32 \L ogfile s

D. \ e tc

T h e de fa u lt P e r fo rm a n c e ta b op tim iz e s th e W e b s
e rv e r fo r how m a ny h its e a c h da y ?

A . L e s s th a n 10 ,000

B . L e s s th a n 50 ,0 0 0 C . L e s s th a n 100 ,000

D . M o re th a n 100 ,000

H o w m a ny S M T P s ite s c a n A rno ld c o nfigure on th e s e

rv e r fo r th e S M T P se rv ic e ?
1. 1
2. 1 0 C . 100

D . U n lim ite d s ite s

A nn is try in g to f ind a n O D B C - c o m p lia nt da ta ba s e

. W h ic h tw o of th e fo llo w in g are ex am p le s o f s u ch ?
1. E x c e l B . A cce s s

C. Q & A

D. S Q L

2 . R ita is try in g to c re a te .ID C file s fo r th e f irs t t
im e . W h ic h o f th e fo l lo w in g f ie lds a re re qu ire d in thos e f ile s ?

A . C on te n t B . T e m p la te C . P a ssw o rd

D. M a x F ie ld S iz e E . D a ta s ourc e

In w h a t m a nne r is O D B C im p le m e n te d on I IS ?
1. As a n e x te n s io n B . A s a n a d d - in

C . As a n AP I

D. As a s n a p - in

W h ic h ty pe s of logon s e c u r ity a re a llo w e d be tw e e n

I IS a nd S Q L ?
1. C le a r te x t B . M u ltip le C . S ta nda rd

D . In te g rated

E . C o n c en trate d

5 . W h at c h aracte r m u s t p reced e e ach lin e o f a S Q L S

ta te m e n t in a n .ID C f ile if th a t p o rtio n is o c c u p y in g m u ltip le lin e s ?
1. $
2. &

C. +

D. #

E. /

In w h ic h f i le w o u ld a n a d m in is tra to r be m o s t lik
e ly to f ind th e M a x R e c o rd s p a ra m e te r?

A . S y s te m .id c

B. S y s te m . id q

C. S y s te m . h tx D . S y s te m .h tm E . S y s te m .h tx

In w h ic h f ile w ou ld a n a d m in is tra to r be m o s t l ike
ly to f ind th e C i C ode P a ge p a ra m e te r?

A . S y s te m .id c

B. S y s te m . id q

C. S y s te m . h tx D . S y s te m .h tm E . S y s te m .h tx

A c tive S e rv e r ta gs be g in w ith w h a t c h a ra c te r ( s

) ?
1. [
2. <
3. %
4. < %
5. [%
A c tive S e rv e r ta gs a re a ls o know n a s w h ic h of th e fo

llo w ing ? A . P r im a ry s c r ipt c o m m a nds

B . L oops C . D LLs

D . C ond itiona l E x e c u tiv e s

L inda is try ing to f ind a c o m m a nd- lin e s c r ip ting hos
t, a n d J a m e s in s is ts th a t

one c a m e w ith I IS . W h a t is th e na m e of th e c o m m a nd- l ine s c r ip ting hos t?

W s c r ip t
S s c r ip t
C s c r ip t
C n s c r ip t

E rne s tin e w ou ld lik e to a u to m a te th e us e of R e port W

r ite r a nd U s a g e Im port. W h ic h to o l w ill a llo w h e r to d o th is a t h e r s ite ?
1. AT
2. S c h e d u le r
3. C ro n
4. T im e r

2 . J o an n is afte r th e b e s t s p eed p e r fo rm an ce o n h
e r s e rv er s h e c a n g e t. W h ic h logg ing op tio n s hou ld s h e c hoo s e if s p e e d pe r form a nc e is he r on ly re qu ire m e n t?

A . T h re a d -b a s e d B . T a s k - b as ed

C . F ile - b as ed

D. ODB C - b a s e d

5 3 . W h ic h u tility is u s e d to re v ie w runn ing th re a d s a nd proc e s s e s ?

A . In te rn e t S e rv ic e M a n a g e r B . P e rfo rm a n c e M o n ito r

C . T a s k M a na ge r

D . S e rv e r M a na ge r

C a r l ha s 180 ,000 doc um e n ts th a t he w a n ts Inde x S e rv
e r to inde x. H o w m u c h R A M s hou ld be c ons id e re d th e ba re m in im u m re qu ire m e n t?

A . 128M B B . 64M B C . 48M B D . 32M B

E. I 6 M B

B u d know s th a t he is lo w on d is k s p a c e a nd ha s orde re
d ne w d is k s to re p la c e h is e x is t in g o n e s . U n til th e y c o m e in , h o w e v e r , h e liv e s w ith th e fe a r th a t s p a c e w ill d ro p to o lo w a n d In d e x S e rv e r w ill ceas e in d e x in g f ile s . B e lo w w h a t a m ount of f re e s p a c e doe s th a t oc c u r?

A . 10 pe rc e n t of c o rpus B . 3 pe rc e n t of c o rpus C . 10M B

D. 3 M B

答案与题解

C

# 号用来表示注释 ( 第 4 章 )
C www

.a m a z o n .c o m 地址是一个 F u lly Q u a lif ie d D o m a in N a m e ( F QDN )( 第 1

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4 - 图17 章 )

E

P in g 是用以测试连接的一个实用工具 ( 第 6 章 )
C

FT P 用以上载和下载文件 ( 第 2 章 )
B

NNT P 用以处理新闻组 ( 第 2 章 )
A

SM T P 用以交换邮件 ( 第 2 章 )
D

IU S R _ co m pu te rnam e 是缺省的 FT P 匿名帐号 ( 第 2 章 )
D

IU S R _c om po te rna m e 是缺省的 W W W 匿名帐号 ( 第 2 章 )
A

, C F QDN 包含主机名和公司名 ( 第 1 章 )
C

D _ S_ Se rv e r是一个 N e t B IO S 名 ( 第 1 章 )
C

In te r计算机安装 IIS 要求最小 3 2 M B RA M ( 第 2 章 )
D

In te l计算机安装 IIS 要求最小 90 M H z ( 第 2 章 )
B

A lpha 计算机安装 IIS 要求最小 4 8 M B RA M ( 第 2 章 )
C

U s e r M a n a g e r fo r D o m a in s 用以给用户帐号分配 NT F S 权限 ( 第 3 章 )
D

P e rfo rm a n c e M o n ito r用以检查 IIS 服务和资源使用情况 ( 第 6 章 )
E

按 C tr l+ A lt+ D e l或右击任务条即可得到 T a s k M a na ge r ( 第 6 章 )
A

TC P 端口 21 是 FT P 服务缺省端口 ( 第 7 章 )
C

TC P 端口 80 是 W W W 服务的缺省端口 ( 第 7 章 )
B

, C FT P 列表可以 UN IX 或 M S - DO S 格式给出 ( 第 3 章 )
A , B

FT P 主目录可位于该计算机上也可以在一远程共享计算机上 ( 第 3

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4 - 图53 章 )

A
, B , C W W W 主目录可位于该计算机上远程共享计算机上或一个 UR L

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4 - 图56 上 ( 第 3 章 )

B

R e ge d t32 .e x e 可用以编辑 R e g is try ( 第 3 章 )
D

防火墙另一边的客户机得不到 Te ln e t服务 ( 第 7 章 )
C

H TTP 协议使用 TC P / IP 的面向连接通信功能进行数据传输 ( 第 7 章 )
C

B 允许有 30 个子网因此它肯定是正确答案但是其给子网数目扩展留的空间太小因为这是一个 A 类网络 ID 30 个子网中的每一个内都可能有 524 ,286 个主机 ID 因此牺牲一个主机地址位以允许有 62 个子网这时每个子网仍可有 262 ,142 个主机是所需要的 160% ( 第 7 章 )
B

虚拟目录允许多个文件一起显示就好像它们同处一个位置一样 ( 第 3

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4 - 图74 章 )

B

虚拟目录必须驻留在同一域上 ( 第 3 章 )
D

In te rn e t S e rv ic e M a n a g e r可创建虚拟目录 ( 第 3 章 )
C

在单个服务器上容纳多个站点这叫做使用虚拟服务器 ( 第 3 章 )
D

虚拟服务器又叫做多宿主机 ( 第 3 章 )
B

SM T P 的缺省端口为 25( 第 3 章 )
C

NNT P 的张贴认证由 NNT P 来执行 ( 第 3 章 )
B

他找到的目录很可能是一个 NNT P 新闻组 ( 第 3 章 )
B

文件上的 .X IX 扩展名表示该文件是索引文件 ( 第 3 章 )
B

M IM E 映射存放在 R e g is try 中 ( 第 3 章 )
D

按天创建的记录文件名应为 in y y m m dd .log( 第 3 章 )
B

缺省情况下一台服务器允许的 FT P 同时连接数为 1000( 第 3 章 )
C W W

W 记录文件在 % S y s te m R oo t% \ S y s te m 32 \L ogfile s 目录中创建 ( 第 3

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4 - 图100 章 )

C
缺省情况下 P e rfo rm a n c e 选项卡按照每天命中数小于 100 ,000 来优化

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4 - 图103 W e b 站点 ( 第 3 章 )

A

只能将一个 SM T P 站点配置为 SM T P 服务 ( 第 3 章 )
B

, D A cce s s 和 SQ L 是 ODB C 兼容的数据库 ( 第 4 章 )
B

, E T e m p la te 和 D a ta s ourc e 是 .ID C 文件中必需的 ( 第 4 章 )
C

在 IIS 中 ODB C 以一个 AP I的形式存在 ( 第 4 章 )
C

, D 标准和综合登录都允许 ( 第 4 章 )
C

在 .ID C 文件中如果一个 S Q L S ta te m e n t要占多行则每一行的开头都要加 + 号 ( 第 4 章 )
A

M a xR e c ords 是 .ID C 文件中使用的参数 ( 第 4 章 )
B

C i C ode P a ge 是 .ID Q 文件中使用的变量 ( 第 4 章 )
D

A c tiv e S e rv e r标签以 <% 打头 ( 第 5 章 )
A

A c tiv e S e rv e r标签又叫作基本脚本命令 ( 第 5 章 )
C

命令行脚本主机是 C s c r ip t( 第 5 章 )
B

S c he du le r可用以自动使用 R e p o r t W rite r和 U s ag e Im p o r t( 第 6 章 )
C

如果只要求速度性能则应选取文件型记录线程型和任务型都不是正确选择 ( 第 6 章 )
C

T a s k M a na ge r用以监视线程和进程的运行 ( 第 6 章 )
D

应考虑至少使用 3 2 M B RA M ( 第 6 章 )
D

一旦自由磁盘空间小于 3M B Inde x S e rv e r将中止索引文件 ( 第 7 章 )

模 拟 考 试 2 In te rn e t In fo rm a tio n S e rv e r 4

模 拟 考 试 2 In te rn e t In fo rm a tio n S e rv e r 4

答 案 与 题 解

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4

模拟考试 2 In te rn e t In fo rm a tio n S e rv e r 4

答案与题解